Exercise 6.6 Class 11 Math Solutions - Unit 6 Sequences and Series, Punjab Board
Step-by-step solutions to Exercise 6.6, Unit 6: Sequences and Series, for Class 11 Punjab Board students. Covers computing the single Geometric Mean G = ±√(ab) between two numbers, inserting n Geometric Means G₁, G₂, ..., Gₙ between given endpoints, and proving that the product of n geometric means equals the nth power of the single geometric mean worked out question by question.
Exercise Overview
Exercise 6.6 is dedicated to the mathematical theory of Geometric Means (G.M.) within Unit 6 of Class 11 Mathematics. A number G is defined as the Geometric Mean between two non-zero real numbers a and b if the sequence a, G, b forms a Geometric Progression. This condition leads directly to the standard formula G = ±√(ab), with the sign chosen to match the signs of a and b.
The exercise broadens this foundation to the insertion of n intermediate geometric means G₁, G₂, ..., Gₙ between two endpoints a and b. This construction generates an (n + 2)-term geometric progression where the common ratio is r = (b/a)^(1/(n + 1)). Students learn to evaluate each intermediate mean via Gₖ = a · rᵏ and prove vital theoretical theorems, notably establishing that the continuous product of all n inserted geometric means is identically equal to the nth power of the single geometric mean: G₁ · G₂ ··· Gₙ = Gⁿ.
In Punjab Board HSSC Part 1 examinations, Exercise 6.6 is an essential source for Section B short questions (inserting 2, 3, or 4 geometric means) and Section C long questions (proving geometric mean product identities) across Lahore, Rawalpindi, Gujranwala, Faisalabad, and Multan boards. Practicing these step-by-step solutions gives students mastery over radicals and exponential indices for high exam scores.