Exercise 7.1 Class 12 Math Solutions - Unit 7 Kinematics, Punjab Board

Step-by-step solutions to Exercise 7.1, Unit 7: Kinematics, for Class 12 Punjab Board students. Covers rectilinear motion, scalar vs vector kinematic quantities, average and instantaneous velocity, displacement-time (s-t) and velocity-time (v-t) graph analysis, equations of motion under constant acceleration, and vertical free fall and upward projection problems, worked out question by question.

This page provides complete step-by-step solved solutions for Exercise 7.1 of Unit 7: Kinematics, Class 12 Mathematics, for Punjab Board (PCTB / PECTAA). All textbook problems are solved with comprehensive mathematical rigor, covering rectilinear motion along a straight line, distinction between scalar (distance, speed) and vector (displacement, velocity, acceleration) quantities, instantaneous rates \(v = \frac{ds}{dt}\) and \(a = \frac{dv}{dt} = \frac{d^2s}{dt^2}\), gradient and area analysis on \(s\)-\(t\) and \(v\)-\(t\) graphs, derivation and application of constant acceleration equations \(v = u + at\), \(s = ut + \frac{1}{2}at^2\), \(v^2 - u^2 = 2as\), and vertical motion under gravity (free fall from rest and upward projection).
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Exercise Overview

Exercise 7.1 initiates Unit 7: Kinematics in Class 12 Mathematics under the Punjab Board PCTB / PECTAA curriculum by analyzing rectilinear motion-the motion of particles along a one-dimensional straight-line trajectory. The exercise formally distinguishes scalar physical quantities (distance traveled, average speed (v_{\text{avg}} = \frac{\text{total distance}}{\text{total time}})) from vector quantities (displacement (\vec{s}), average velocity (\vec{v}_{\text{avg}} = \frac{\Delta \vec{s}}{\Delta t}), and instantaneous velocity (\vec{v} = \frac{d\vec{s}}{dt})). Instantaneous acceleration is defined as the first time derivative of velocity and the second time derivative of position: (\vec{a} = \frac{d\vec{v}}{dt} = \frac{d^2\vec{s}}{dt^2} = v\frac{dv}{ds}).

The exercise thoroughly develops graphical kinematic interpretations: on a displacement-time ((s)-(t)) graph, the slope of the tangent at any point yields the instantaneous velocity ((\frac{ds}{dt})); on a velocity-time ((v)-(t)) graph, the gradient represents instantaneous acceleration ((\frac{dv}{dt})), while the definite integral or area under the curve represents the net displacement ((\int v \, dt)). For uniform motion with constant acceleration (a), the standard kinematic equations are derived and applied: (v = u + at), (s = ut + \frac{1}{2}at^2), and (v^2 - u^2 = 2as). Vertical motion under gravity ((a = -g)) is investigated for free fall from rest ((u = 0 \implies v = \sqrt{2gh})) and vertical upward projection ((H_{\max} = \frac{u^2}{2g}), total time of flight (T = \frac{2u}{g})).

For Punjab Board HSSC Part 2 examinations across all nine educational divisions (Lahore, Rawalpindi, Gujranwala, Faisalabad, Multan, Bahawalpur, Sargodha, Sahiwal, and D.G. Khan), Exercise 7.1 is a fundamental source of Section B Short Questions (graph gradient calculations, velocity/acceleration differentiations, stopping distance problems) and Section C Long Questions (multi-stage rectilinear journeys and vertical motion systems under gravity). These step-by-step solutions provide rigorous mathematical calculus derivations, clear coordinate conventions, and exact algebraic evaluations for every textbook problem.

FAQs

Are these Exercise 7.1 solutions according to the Punjab Board syllabus?
Yes. These solutions follow the Punjab Curriculum and Textbook Board (PCTB / PECTAA) syllabus for Class 12 Mathematics, matching all kinematics concepts and rectilinear motion problems in Unit 7, Exercise 7.1 for the 2026-2027 session.
Do these solutions cover every question in Exercise 7.1?
Yes, every question in Exercise 7.1 is completely solved, including velocity/acceleration derivations, s-t and v-t graph interpretations, constant acceleration equations, and vertical projectile motion.
Are the solutions step-by-step?
Yes. Each problem details the mathematical procedure-calculating derivatives v = ds/dt and a = dv/dt, finding gradients and areas under motion curves, and applying kinematic equations v = u + at, s = ut + (1/2)at², and v² - u² = 2as.
Can students read these solutions online?
Yes, the complete Exercise 7.1 solution set is available to read online directly on this page on MaryamNotes.pk with zero software download or registration required.
Are these solutions based on the latest PCTB / PECTAA syllabus?
Yes, they are strictly aligned with the updated PCTB and PECTAA Mathematics curriculum for Class 12 HSSC Part 2 for the 2026-2027 academic year.
Are these solutions free for students?
Yes, Exercise 7.1 solutions on this page are completely free for all Intermediate Part 2 students across Lahore, Rawalpindi, Gujranwala, Faisalabad, Multan, and all other Punjab boards.