Exercise 6.1 Class 12 Math Solutions - Unit 6 Conics, Punjab Board

Step-by-step solutions to Exercise 6.1, Unit 6: Conics, for Class 12 Punjab Board students. Covers standard and general forms of the equation of a circle, parametric equations, working rules to calculate centre and radius, equation of a circle with given diameter endpoints, and finding circle equations under four fundamental geometric constraint cases, worked out question by question.

This page provides complete step-by-step solved solutions for Exercise 6.1 of Unit 6: Conics, Class 12 Mathematics, for Punjab Board (PCTB / PECTAA). All textbook problems are rigorously worked out, including standard form \((x - h)^2 + (y - k)^2 = r^2\), general form \(x^2 + y^2 + 2gx + 2fy + c = 0\) with centre \((-g, -f)\) and radius \(r = \sqrt{g^2 + f^2 - c}\), parametric equations \(x = r\cos\theta, y = r\sin\theta\), diameter form \((x - x_1)(x - x_2) + (y - y_1)(y - y_2) = 0\), and the four standard geometric constraint cases (circles through 3 non-collinear points, centre on a given line, tangent at a given point, and touching a given line).
Advertisement

Exercise Overview

Exercise 6.1 opens Unit 6: Conics in Class 12 Mathematics under the Punjab Board PCTB / PECTAA curriculum by introducing the circle as the foundational conic section formed by intersecting a right circular cone with a plane perpendicular to the cone's axis. The exercise establishes the standard central equation of a circle ((x - h)^2 + (y - k)^2 = r^2) with centre (C(h, k)) and radius (r), as well as the standard parametric equations (x = h + rcos heta) and (y = k + rsin heta). Expanding the central form yields the general second-degree equation of a circle (x^2 + y^2 + 2gx + 2fy + c = 0), whose centre is (C(-g, -f)) and radius is (r = sqrt{g^2 + f^2 - c}). Students categorize circles as real ((g^2 + f^2 - c > 0)), point ((g^2 + f^2 - c = 0)), or imaginary ((g^2 + f^2 - c < 0)).

The exercise systematically derives the equation of a circle when the endpoints of a diameter (A(x_1, y_1)) and (B(x_2, y_2)) are given, expressed via vector orthogonality as ((x - x_1)(x - x_2) + (y - y_1)(y - y_2) = 0). Furthermore, students master the four classical geometric constraint cases required to determine the unique three parameters (g, f,) and (c): Case 1 (a circle passing through three non-collinear points), Case 2 (a circle passing through two points with its centre lying on a specified line), Case 3 (a circle passing through two points with a given tangent line at one of those points), and Case 4 (a circle passing through two points and touching a given straight line).

For Punjab Board HSSC Part 2 examinations across all nine educational divisions (Lahore, Rawalpindi, Gujranwala, Faisalabad, Multan, Bahawalpur, Sargodha, Sahiwal, and D.G. Khan), Exercise 6.1 provides essential Section B Short Questions (extracting centre/radius, forming parametric representations, diameter equations) and high-yield Section C Long Questions (solving simultaneous three-parameter systems for circles under geometric constraints). These step-by-step solutions provide rigorous algebraic calculations and clear geometric reasoning for every textbook question.

FAQs

Are these Exercise 6.1 solutions according to the Punjab Board syllabus?
Yes. These solutions follow the Punjab Curriculum and Textbook Board (PCTB / PECTAA) syllabus for Class 12 Mathematics, matching all circle equations and geometric conditions in Unit 6, Exercise 6.1 for the 2026-2027 session.
Do these solutions cover every question in Exercise 6.1?
Yes, all textbook problems in Exercise 6.1 are fully solved, including standard/general forms, centre-radius extraction, parametric conversions, diameter endpoints, and all 4 circle determination cases.
Are the solutions step-by-step?
Yes. Each problem provides systematic steps-setting up general equations x² + y² + 2gx + 2fy + c = 0, determining g, f, and c from given geometric conditions, finding centre (-g, -f) and radius √(g² + f² - c), and verifying concentric or tangency relations.
Can students read these solutions online?
Yes, the complete Exercise 6.1 solution set is available to read online directly on this page on MaryamNotes.pk with zero software installation or download required.
Are these solutions based on the latest PCTB / PECTAA syllabus?
Yes, they are strictly aligned with the updated PCTB and PECTAA Mathematics curriculum for Class 12 HSSC Part 2 for the 2026-2027 academic year.
Are these solutions free for students?
Yes, Exercise 6.1 solutions on this page are completely free for all Intermediate Part 2 students across Lahore, Rawalpindi, Gujranwala, Faisalabad, Multan, and all other Punjab boards.