Exercise 6.2 Class 12 Math Solutions - Unit 6 Conics, Punjab Board

Step-by-step solutions to Exercise 6.2, Unit 6: Conics, for Class 12 Punjab Board students. Covers equations of tangents and normals to a circle, standard replacement rules, position of a point with respect to a circle, line-circle intersection cases, condition of tangency c² = r²(1 + m²), coordinates of point of contact, and formulas for the length of tangents from an external point, worked out question by question.

This page provides complete step-by-step solved solutions for Exercise 6.2 of Unit 6: Conics, Class 12 Mathematics, for Punjab Board (PCTB / PECTAA). All questions are solved in detail, covering equations of tangents \(xx_1 + yy_1 = r^2\) and \(xx_1 + yy_1 + g(x + x_1) + f(y + y_1) + c = 0\), equations of normals, determining point positions relative to circles (interior, on, exterior), line-circle intersections and tangency condition \(c^2 = r^2(1 + m^2)\), coordinates of the point of contact, finding tangent equations from an external point, and computing the length of tangents \(\sqrt{x_1^2 + y_1^2 + 2gx_1 + 2fy_1 + c}\).
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Exercise Overview

Exercise 6.2 of Unit 6: Conics in Class 12 Mathematics under the Punjab Board PCTB / PECTAA curriculum focuses on the geometric properties of tangents and normals to a circle. For a standard circle (x^2 + y^2 = r^2), the equation of the tangent at point (P(x_1, y_1)) is (xx_1 + yy_1 = r^2), while the equation of the normal is (y - y_1 = rac{y_1}{x_1}(x - x_1)), simplifying to (x y_1 - y x_1 = 0) (demonstrating that the normal to a circle always passes through its centre). For the general circle (x^2 + y^2 + 2gx + 2fy + c = 0), the equation of the tangent at (P(x_1, y_1)) is constructed via the fundamental replacement rules ((x^2 o xx_1), (y^2 o yy_1), (2x o x + x_1), (2y o y + y_1)) as (xx_1 + yy_1 + g(x + x_1) + f(y + y_1) + c = 0), with its normal passing through ((-g, -f)) having slope ( rac{y_1 + f}{x_1 + g}).

The exercise thoroughly investigates the position of a point (P(x_1, y_1)) with respect to a circle using the power value (S_1 = x_1^2 + y_1^2 + 2gx_1 + 2fy_1 + c): the point lies outside if (S_1 > 0), on the circle if (S_1 = 0), and inside if (S_1 < 0). The intersection of a line (y = mx + c) with a circle (x^2 + y^2 = r^2) is analyzed through the discriminant of the resulting quadratic: two real points ((Delta > 0)), one contact point / tangent line ((Delta = 0 implies c^2 = r^2(1 + m^2))), or no real intersection ((Delta < 0)). The coordinates of the point of contact are derived as (left(- rac{mr^2}{c}, rac{r^2}{c} ight)), and the length of a tangent drawn from an external point (P(x_1, y_1)) is given by (L = sqrt{S_1} = sqrt{x_1^2 + y_1^2 + 2gx_1 + 2fy_1 + c}).

For Punjab Board HSSC Part 2 examinations across all nine educational divisions (Lahore, Rawalpindi, Gujranwala, Faisalabad, Multan, Bahawalpur, Sargodha, Sahiwal, and D.G. Khan), Exercise 6.2 is essential for Section B Short Questions (evaluating point position, finding tangent length, writing tangent/normal equations) and Section C Long Questions (finding tangents from an external point, finding common tangents, and applying tangency condition proofs). These step-by-step solutions provide rigorous derivations, quadratic discriminant checks, and complete algebraic details for every textbook question.

FAQs

Are these Exercise 6.2 solutions according to the Punjab Board syllabus?
Yes. These solutions follow the Punjab Curriculum and Textbook Board (PCTB / PECTAA) syllabus for Class 12 Mathematics, matching all tangent, normal, and intersection concepts in Unit 6, Exercise 6.2 for the 2026-2027 session.
Do these solutions cover every question in Exercise 6.2?
Yes, every question in Exercise 6.2 is completely solved, including tangent and normal equations at a point on the circle, finding tangents from an external point, determining length of tangents, and applying tangency conditions.
Are the solutions step-by-step?
Yes. Each problem is worked out with full analytical steps-applying replacement rules x² → xx₁, y² → yy₁, 2x → x + x₁, 2y → y + y₁, evaluating quadratic discriminant for line-circle intersection, calculating normal slopes, and finding tangent lengths.
Can students read these solutions online?
Yes, the complete Exercise 6.2 solution set is available to read online directly on this page on MaryamNotes.pk with zero software download or registration required.
Are these solutions based on the latest PCTB / PECTAA syllabus?
Yes, they are strictly aligned with the updated PCTB and PECTAA Mathematics curriculum for Class 12 HSSC Part 2 for the 2026-2027 academic year.
Are these solutions free for students?
Yes, Exercise 6.2 solutions on this page are completely free for all Intermediate Part 2 students across Lahore, Rawalpindi, Gujranwala, Faisalabad, Multan, and all other Punjab boards.